Correct order of reactivity in nucleophilic a | vedclass

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(A) The reactivity of carbonyl compounds towards nucleophilic addition depends on the magnitude of the positive charge on the carbonyl carbon.Electron

Vedclass · Accepted Answer

$iii > i > ii > iv$

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(A) The reactivity of carbonyl compounds towards nucleophilic addition depends on the magnitude of the positive charge on the carbonyl carbon.Electron-withdrawing groups $(-NO_2)$ increase the electrophilicity of the carbonyl carbon,thereby increasing reactivity.Electron-donating groups $(-CH_3)$ decrease the electrophilicity,thereby decreasing reactivity.Steric hindrance also plays a role; ketones $(iv)$ are less reactive than aldehydes due to steric and electronic factors.Comparing the compounds:(iii) $p$-Nitrobenzaldehyde: $-NO_2$ is a strong electron-withdrawing group,making it the most reactive.$(i)$ Benzaldehyde: No substituent.(ii) $p$-Methylbenzaldehyde: $-CH_3$ is an electron-donating group,making it less reactive than benzaldehyde.(iv) Acetophenone: It is a ketone,which is less reactive than aldehydes due to the $+I$ effect of the methyl group and steric hindrance.The order is: $(iii) > (i) > (ii) > (iv)$.

Correct order of reactivity in nucleophilic addition reaction is:
$(i)$ Benzaldehyde
(ii) $p$-Methylbenzaldehyde
(iii) $p$-Nitrobenzaldehyde
(iv) Acetophenone

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Correct order of reactivity in nucleophilic addition reaction is:$(i)$ Benzaldehyde(ii) $p$-Methylbenzaldehyde(iii) $p$-Nitrobenzaldehyde(iv) Acetophenone