The correct order of strength of $\pi-$ bond$(s)$ is:
$I$. $BO_3^{-3} < CO_3^{-2} < NO_3^{-}$
$II$. $ClO_4^{-} > SO_4^{-2} > PO_4^{-3}$
$III$. $BF_3 > BCl_3 > BBr_3$
$IV$. $AlCl_3 < BCl_3$

The formal charges of $N_{(1)}$,$N_{(2)}$ and $O$ atoms in the structure shown below are respectively:
$:N_{(1)}=N_{(2)}=\ddot{O}:$

The correct increasing order of the total number of $\sigma$ and $\pi$ bonds in the following structures is:
$I. \ H_2S_2O_6, \ II. \ H_2SO_3, \ III. \ H_2SO_5$

Match the following molecules in Column $I$ with the number of lone pairs on their central atom in Column $II$.

Column $I$ (Molecules)	Column $II$ (Number of lone pairs on central atom)
$A. \ NH_3$	$1. \ \text{Two}$
$B. \ H_2O$	$2. \ \text{Three}$
$C. \ XeF_2$	$3. \ \text{Zero}$
$D. \ CH_4$	$4. \ \text{Four}$
	$5. \ \text{One}$

The ionization enthalpy of $Na^{+}$ formation from $Na_{(g)}$ is $495.8 \ kJ \ mol^{-1},$ while the electron gain enthalpy of $Br_{(g)}$ is $-325.0 \ kJ \ mol^{-1}$. Given the lattice enthalpy of $NaBr_{(s)}$ is $-728.4 \ kJ \ mol^{-1}$. The energy for the reaction $Na_{(g)} + Br_{(g)} \rightarrow NaBr_{(s)}$ is $(-) \dots \dots \dots \dots \dots \times 10^{-1} \ kJ \ mol^{-1}$.

Which of the following is the correct increasing order of $O-O$ bond length in $O_2$,$O_3$,and $H_2O_2$?