The correct relationship between heat of fusi | vedclass

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(C) According to Hess's Law,the enthalpy change for a process is the same whether it occurs in one step or multiple steps.Sublimation is the direct co

Vedclass · Accepted Answer

$\Delta H_{sub} = \Delta H_{vap} + \Delta H_{fus}$

Vedclass · Answer

(C) According to Hess's Law,the enthalpy change for a process is the same whether it occurs in one step or multiple steps.Sublimation is the direct conversion of a solid to a gas: $	ext{Solid} ightarrow 	ext{Gas} (\Delta H_{sub})$.This process can also occur in two steps: $	ext{Solid} ightarrow 	ext{Liquid} (\Delta H_{fus})$ followed by $	ext{Liquid} ightarrow 	ext{Gas} (\Delta H_{vap})$.Therefore,the total enthalpy change is the sum of the individual steps: $\Delta H_{sub} = \Delta H_{fus} + \Delta H_{vap}$.

The correct relationship between heat of fusion $(\Delta H_{fus})$,heat of vaporization $(\Delta H_{vap})$,and heat of sublimation $(\Delta H_{sub})$ is:

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