The correct set of four quantum numbers for t | vedclass

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Question

(A) The atomic number of rubidium $(Rb)$ is $37$.The electronic configuration of $Rb$ is: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^2, 4p^6, 5s^1$.Th

Vedclass · Accepted Answer

$5, 0, 0, +\frac{1}{2}$

Vedclass · Answer

(A) The atomic number of rubidium $(Rb)$ is $37$.The electronic configuration of $Rb$ is: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^2, 4p^6, 5s^1$.The valence electron is in the $5s$ orbital.For the $5s^1$ electron:Principal quantum number $(n) = 5$.Azimuthal quantum number $(l)$ for $s$-orbital $= 0$.Magnetic quantum number $(m_l) = 0$.Spin quantum number $(m_s) = +\frac{1}{2}$ (or $-\frac{1}{2}$).Thus,the set of quantum numbers is $(5, 0, 0, +\frac{1}{2})$.

The correct set of four quantum numbers for the valence electron of rubidium $(Z = 37)$ is:

Similar Questions

Which of the following orbitals does not have any directional properties?

Given,
$(A)$ $n=5, m_l=-1$
$(B)$ $n=3, l=2, m_l=-1, m_s=+\frac{1}{2}$
The maximum number of electron$(s)$ in an atom that can have the quantum numbers as given in $(A)$ and $(B)$ respectively are:

The correct order of energy of $2s$-orbitals in $H$,$Li$,$Na$ and $K$ is:

The electronic configuration of three elements $A$,$B$,and $C$ are given below. Stable form of $A$ may be represented by the formula:
$A : 1s^2, 2s^2, 2p^6$
$B : 1s^2, 2s^2, 2p^6, 3s^2, 3p^3$
$C : 1s^2, 2s^2, 2p^6, 3s^2, 3p^5$

Which of the following is violating Hund's rule?

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