The correct stability order of the given taut | vedclass

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(C) In general,the keto form $(II)$ is more stable than the enol forms ($I$ and $III$) due to the higher bond energy of the $C=O$ bond compared to the

Vedclass · Accepted Answer

$II > I > III$

Vedclass · Answer

(C) In general,the keto form $(II)$ is more stable than the enol forms ($I$ and $III$) due to the higher bond energy of the $C=O$ bond compared to the $C=C$ bond.Between the two enol forms ($I$ and $III$),structure $(I)$ is more stable than structure $(III)$.Structure $(III)$ contains a double bond at the bridgehead position of a bicyclic system involving a three-membered ring,which violates Bredt's rule. This introduces significant angle strain and makes the structure highly unstable.Therefore,the correct stability order is $II > I > III$.

The correct stability order of the given tautomers is:

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