Which of the following statement(s) is/are co | vedclass

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(D) $1$. In an acidic medium,$K_2Cr_2O_7$ acts as a strong oxidizing agent and oxidizes $I^-$ to $I_2$: $Cr_2O_7^{2-} + 14H^+ + 6I^- \rightarrow 2Cr^{

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All of the above.

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(D) $1$. In an acidic medium,$K_2Cr_2O_7$ acts as a strong oxidizing agent and oxidizes $I^-$ to $I_2$: $Cr_2O_7^{2-} + 14H^+ + 6I^- ightarrow 2Cr^{3+} + 7H_2O + 3I_2$. Thus,statement $A$ is correct.$2$. $K_2Cr_2O_7$ is a primary standard used in redox titrations to estimate $Fe^{2+}$ ions: $Cr_2O_7^{2-} + 14H^+ + 6Fe^{2+} ightarrow 2Cr^{3+} + 6Fe^{3+} + 7H_2O$. Thus,statement $B$ is correct.$3$. The n-factor for $K_2Cr_2O_7$ in an acidic medium is $6$ (change in oxidation state of $Cr$ from $+6$ to $+3$ for two $Cr$ atoms). Since $N = M 	imes n	ext{-factor}$,we have $N = M 	imes 6$,which implies $M = N/6$. Thus,statement $C$ is correct.$4$. Since all statements are correct,the answer is $D$.

List-$I$ (Aqueous solution of salt)	List-$II$ (Color)
$A$. $FeSO_4 \cdot 7H_2O$	$i$. Green
$B$. $NiCl_2 \cdot 4H_2O$	$ii$. Pale pink
$C$. $MnCl_2 \cdot 4H_2O$	$iii$. Blue
$D$. $CoCl_2 \cdot 6H_2O$	$iv$. Light green
$E$. $Cu_2Cl_2$	$v$. Pink
	$vi$. Colorless

Which of the following statement$(s)$ is/are correct?

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