The cross-section of a prism is an equilateral triangle $ABC$ as shown in the figure. The minimum deviation is observed when the angle of incidence is equal to the prism angle. The time taken by light to travel from the midpoint $P$ of $BC$ to $A$ is $..... \times 10^{-10} \, s$. (Given: speed of light in vacuum $= 3 \times 10^8 \, m/s$ and $\cos 30^{\circ} = \frac{\sqrt{3}}{2}$)

At what angle of incidence should a ray of light be incident on a face of an equilateral prism if the angle of minimum deviation is $46^{\circ}$ (in $^{\circ}$)?

For a prism with a prism angle of $60^\circ$ and a refractive index of $\mu = \sqrt{2}$,the angle of minimum deviation is .......... $^\circ$.

$A$ ray of light is incident at an angle '$i$' on one face of a prism of small angle '$A$' and emerges normally from the other surface. If '$\mu$' is the refractive index of the material of the prism,then the angle of incidence is:

$A$ prism of refractive index $n_{1}$ and another prism of refractive index $n_{2}$ are stuck together (as shown in the figure). $n_{1}$ and $n_{2}$ depend on $\lambda$, the wavelength of light, according to the relation:
${n}_{1}=1.2+\frac{10.8 \times 10^{-14}}{\lambda^{2}} \text{ and } {n}_{2}=1.45+\frac{1.8 \times 10^{-14}}{\lambda^{2}}$
The wavelength for which rays incident at any angle on the interface $BC$ pass through without bending at that interface will be $....\,nm.$

At what angle should a ray of light be incident on the face of a prism of refracting angle $60^{\circ}$ so that it just suffers total internal reflection at the other face? The refractive index of the material of the prism is $1.524$.