The current in the 2, Omega resistance shown | vedclass

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(C) At $t = 0$, the inductor acts as an open circuit because it opposes any sudden change in current. The circuit consists of the $10\, V$ battery, $2

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$\frac{5}{3}\, A, 5\, A$

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(C) At $t = 0$, the inductor acts as an open circuit because it opposes any sudden change in current. The circuit consists of the $10\, V$ battery, $2\, \Omega$ resistor, and $4\, \Omega$ resistor in series.Total resistance $R_{eq} = 2\, \Omega + 4\, \Omega = 6\, \Omega$.The current $I = \frac{V}{R_{eq}} = \frac{10\, V}{6\, \Omega} = \frac{5}{3}\, A$.At $t = \infty$, the inductor acts as a short circuit (a wire with zero resistance) because the current has reached a steady state. The $4\, \Omega$ resistor is bypassed by the short-circuited inductor.The circuit now consists of only the $10\, V$ battery and the $2\, \Omega$ resistor.The current $I = \frac{10\, V}{2\, \Omega} = 5\, A$.Thus, the currents are $\frac{5}{3}\, A$ and $5\, A$ respectively.

The current in the $2\, \Omega$ resistance shown in the figure is:
$(a)$ Just after the closing of the key.
$(b)$ $A$ long time after the closing of the key.

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The current in the $2\, \Omega$ resistance shown in the figure is:$(a)$ Just after the closing of the key.$(b)$ $A$ long time after the closing of the key.