Cyclohexene on oxidation with KMnO_4 in dil. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The oxidation of cyclohexene with $KMnO_4$ in the presence of dilute $H_2SO_4$ is a vigorous reaction that causes the cleavage of the double bond.

Vedclass · Accepted Answer

Adipic acid

Vedclass · Answer

(D) The oxidation of cyclohexene with $KMnO_4$ in the presence of dilute $H_2SO_4$ is a vigorous reaction that causes the cleavage of the double bond. Initially,the double bond is broken to form an intermediate,which is further oxidized to a dicarboxylic acid. Specifically,cyclohexene undergoes oxidative cleavage to yield $Hexanedioic \ acid$,commonly known as $Adipic \ acid$ $(HOOC-(CH_2)_4-COOH)$.

Cyclohexene on oxidation with $KMnO_4$ in dil. $H_2SO_4$ forms.

Similar Questions

Which of the following products is not formed during the reaction: $CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{Br_2/aq. NaCl}$?

Identify the major product formed when $2-$Methylhexan$-3-$ol is heated with concentrated sulphuric acid.

Assertion : $1$-Butene on reaction with $HBr$ in the presence of a peroxide produces $1$-bromobutane.
Reason : It involves the free radical mechanism.

The reaction conditions used for converting $1, 2-$dibromoethane to ethene are

$A$ hydrocarbon contains $86\%$ carbon. $488 \ mL$ of the hydrocarbon weighs $1.68 \ g$ at $STP$. Then the hydrocarbon is an:

Vedclass Test Series

Exam Paper Generator

Online Exam Module