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What is the major product $Y$ in the following reaction sequence?
$C_6H_5CONH_2$ $\xrightarrow[\text{Pyridine } 70^{\circ}C]{C_6H_5SO_2Cl} X$ $\xrightarrow[(ii) Br_2, FeBr_3]{(i) H_3O^+} Y$

Assertion: $CH_3COCl$ is converted to $CH_3CONH_2$ on reaction with $NH_3$.
Reason: $Cl^{-}$ is a stronger nucleophile and better leaving group.

Which ester is used as a medicine?

The reaction of $HCOOH$ with conc. $H_2SO_4$ gives

Explain the mechanism of action for the esterification of carboxylic acids.

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