Determine the decreasing order of the acidic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The acidity of a compound depends on the stability of its conjugate base. Electron-withdrawing groups $(EWG)$ increase acidity by stabilizing the

Vedclass · Accepted Answer

$Q > R > P > S$

Vedclass · Answer

(B) The acidity of a compound depends on the stability of its conjugate base. Electron-withdrawing groups $(EWG)$ increase acidity by stabilizing the negative charge,while electron-donating groups $(EDG)$ decrease acidity by destabilizing it.$Q$ is $p$-hydroxybenzoic acid. The $-COOH$ group is a strong $EWG$,making it the most acidic.$R$ is $p$-hydroxybenzaldehyde. The $-CHO$ group is an $EWG$,but less acidic than the carboxylic acid group.$P$ is hydroquinone ($p$-dihydroxybenzene). The $-OH$ group at the para position acts as an $EDG$ via resonance,but it is less donating than the alkyl group.$S$ is $p$-cresol ($p$-methylphenol). The $-CH_3$ group is an $EDG$ via hyperconjugation and inductive effect,making it the least acidic.Therefore,the decreasing order of acidity is $Q > R > P > S$.

Determine the decreasing order of the acidic nature of the given compounds $P$,$Q$,$R$,and $S$.

Similar Questions

Acetamide is

Identify the correct order of boiling points of the following compounds: $CH_3CH_2CH_2CH_2OH$ $(1)$,$CH_3CH_2CH_2CHO$ $(2)$,$CH_3CH_2CH_2COOH$ $(3)$.

Which among the following carboxylic acids is the strongest acid?

Which of the following will not produce acetamide upon reaction with ammonia?

If the rate of the reaction,$R-CO-Z + Nu^- \rightarrow R-CO-Nu + Z^-$ is fastest,then $Z$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module