The decreasing order of C-C bond length is:I. | vedclass

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(A) The bond length is inversely proportional to the bond order.$I.$ $C_2H_4$ $(CH_2=CH_2)$: Bond order = $2$, Bond length $\approx 134 \ pm$$II.$ $C_

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$IV > III > I > II$

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(A) The bond length is inversely proportional to the bond order.$I.$ $C_2H_4$ $(CH_2=CH_2)$: Bond order = $2$, Bond length $\approx 134 \ pm$$II.$ $C_2H_2$ $(CH \equiv CH)$: Bond order = $3$, Bond length $\approx 120 \ pm$$III.$ $C_6H_6$ (Benzene): Bond order = $1.5$, Bond length $\approx 139 \ pm$$IV.$ $C_2H_6$ $(CH_3-CH_3)$: Bond order = $1$, Bond length $\approx 154 \ pm$Comparing the bond orders: $C_2H_6 (1) Therefore, the decreasing order of bond length is: $IV (154 \ pm) > III (139 \ pm) > I (134 \ pm) > II (120 \ pm)$.

List-$I$	List-$II$
$(A)$ $C_{2}H_{4}$	$(I)$ $3\sigma$ bonds, $2\pi$ bonds
$(B)$ $C_{2}H_{2}$	$(II)$ $3\sigma$ bonds, $1$ lone pair
$(C)$ $CH_{4}$	$(III)$ $4\sigma$ bonds
$(D)$ $NH_{3}$	$(IV)$ $5\sigma$ bonds, $1\pi$ bond

The decreasing order of $C-C$ bond length is:
$I.$ $C_2H_4$ $II.$ $C_2H_2$
$III.$ $C_6H_6$ $IV.$ $C_2H_6$

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The decreasing order of $C-C$ bond length is:$I.$ $C_2H_4$ $II.$ $C_2H_2$$III.$ $C_6H_6$ $IV.$ $C_2H_6$