Deepa drives a bike at an average speed of 30 | vedclass

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Question

(A) The distance between the starting point and the destination is calculated as: $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time} = 30 \, km/h 	im

Vedclass · Accepted Answer

$54 \, minutes$

Vedclass · Answer

(A) The distance between the starting point and the destination is calculated as: $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time} = 30 \, km/h 	imes 6 \, h = 180 \, km$.Hema's original speed is: $	ext{Speed} = \frac{180 \, km}{4 \, h} = 45 \, km/h$.Deepa's new speed is $30 + 10 = 40 \, km/h$. The new time taken by Deepa is: $	ext{Time} = \frac{180 \, km}{40 \, km/h} = 4.5 \, h = 4 \, hours \, 30 \, minutes$.Hema's new speed is $45 + 5 = 50 \, km/h$. The new time taken by Hema is: $	ext{Time} = \frac{180 \, km}{50 \, km/h} = 3.6 \, h = 3 \, hours \, 36 \, minutes$.The difference in time taken is: $4 \, hours \, 30 \, minutes - 3 \, hours \, 36 \, minutes = 54 \, minutes$.

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