Density of a gas is found to be 5.46 , g / dm | vedclass

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(A) Given:$d_1 = 5.46 \, g / dm^3$$p_1 = 2 \, bar$$T_1 = 27^{\circ} C = 300 \, K$$p_2 = 1 \, bar$ (at $STP$)$T_2 = 273 \, K$ (at $STP$)Using the ideal

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$3.00 \, g / dm^3$

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(A) Given:$d_1 = 5.46 \, g / dm^3$$p_1 = 2 \, bar$$T_1 = 27^{\circ} C = 300 \, K$$p_2 = 1 \, bar$ (at $STP$)$T_2 = 273 \, K$ (at $STP$)Using the ideal gas equation $d = \frac{Mp}{RT}$,we have:$\frac{d_1}{d_2} = \frac{p_1 T_2}{p_2 T_1}$Rearranging for $d_2$:$d_2 = \frac{d_1 p_2 T_1}{p_1 T_2}$Substituting the values:$d_2 = \frac{5.46 	imes 1 	imes 300}{2 	imes 273}$$d_2 = \frac{1638}{546} = 3 \, g / dm^3$Thus,the density at $STP$ is $3 \, g / dm^3$.

Density of a gas is found to be $5.46 \, g / dm^3$ at $27^{\circ} C$ at $2 \, bar$ pressure. What will be density at $STP$?

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