Density of ice is rho and that of water is si | vedclass

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(C) The volume of ice of mass $M$ is given by $V_{	ext{ice}} = \frac{M}{ho}$.When this ice melts into water of the same mass $M$,the volume of the

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$M \left( \frac{1}{\rho} - \frac{1}{\sigma} \right)$

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(C) The volume of ice of mass $M$ is given by $V_{	ext{ice}} = \frac{M}{ho}$.When this ice melts into water of the same mass $M$,the volume of the water is $V_{	ext{water}} = \frac{M}{\sigma}$.Since the density of water $\sigma$ is greater than the density of ice $ho$,the volume of water will be less than the volume of ice.The decrease in volume is $\Delta V = V_{	ext{ice}} - V_{	ext{water}}$.Substituting the expressions,we get $\Delta V = \frac{M}{ho} - \frac{M}{\sigma} = M \left( \frac{1}{ho} - \frac{1}{\sigma} ight)$.

Density of ice is $\rho$ and that of water is $\sigma$. What will be the decrease in volume when a mass $M$ of ice melts?

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