Determine the maximum acceleration in m/s^2 o | vedclass

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(C) The box remains stationary relative to the train floor due to the static frictional force acting on it.Let $m$ be the mass of the box, $a$ be the

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$1.5$

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(C) The box remains stationary relative to the train floor due to the static frictional force acting on it.Let $m$ be the mass of the box, $a$ be the acceleration of the train, and $\mu_s$ be the coefficient of static friction.The force providing the acceleration to the box is the static friction $f_s$.According to Newton's second law, $f_s = m a$.For the box to remain stationary, the static friction must satisfy $f_s \leq \mu_s N$, where $N = m g$ is the normal force.Thus, $m a \leq \mu_s m g$, which simplifies to $a \leq \mu_s g$.The maximum acceleration $a_{\max}$ is given by $a_{\max} = \mu_s g$.Substituting the given values, $a_{\max} = 0.15 	imes 10 \ m/s^2 = 1.5 \ m/s^2$.

Determine the maximum acceleration in $m/s^2$ of the train in which a box lying on its floor will remain stationary, given that the coefficient of static friction between the box and the train's floor is $0.15$. (Take $g = 10 \ m/s^2$)

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