Between the dichloronitronium ion [ONCl_2]^+ | vedclass

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Question

(A) $1$. In $[ONCl_2]^+$,the central atom is $N$. The hybridization of $N$ is $sp^2$ with one double bond to $O$ and two single bonds to $Cl$. The geo

Vedclass · Accepted Answer

$Cl-\hat{N}-Cl > Cl-\hat{S}-Cl$

Vedclass · Answer

(A) $1$. In $[ONCl_2]^+$,the central atom is $N$. The hybridization of $N$ is $sp^2$ with one double bond to $O$ and two single bonds to $Cl$. The geometry is trigonal planar,and the bond angle is approximately $120^{\circ}$.$2$. In $(OSCl_2)$,the central atom is $S$. The hybridization of $S$ is $sp^3$ with one lone pair,one double bond to $O$,and two single bonds to $Cl$. The geometry is trigonal pyramidal. Due to the presence of a lone pair on $S$,the $Cl-S-Cl$ bond angle is compressed to approximately $96^{\circ}-106^{\circ}$.$3$. Comparing the two,$120^{\circ} > 96^{\circ}-106^{\circ}$. Therefore,the bond angle in $[ONCl_2]^+$ is greater than in $(OSCl_2)$.

Between the dichloronitronium ion $[ONCl_2]^+$ and thionyl chloride $(OSCl_2)$,which has a higher $Cl-\hat{X}-Cl$ bond angle? (where $X$ is the central atom $N$ or $S$)

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