The difference between the oxidation numbers | vedclass

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Question

(A) In $Na_2S_4O_6$ (sodium tetrathionate),the structure contains two terminal sulphur atoms bonded to three oxygen atoms each and one hydroxyl group,

Vedclass · Accepted Answer

$5$

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(A) In $Na_2S_4O_6$ (sodium tetrathionate),the structure contains two terminal sulphur atoms bonded to three oxygen atoms each and one hydroxyl group,and two central sulphur atoms bonded to each other.The oxidation number of each terminal sulphur atom is $+5$.The oxidation number of each central sulphur atom is $0$.The difference between the oxidation numbers of the two types of sulphur atoms is $5 - 0 = 5$.The structure is: $O_3S-S-S-SO_3^{2-}$ (or more accurately,$^-O_3S-S-S-SO_3^-$).

The difference between the oxidation numbers of the two types of sulphur atoms in $Na_2S_4O_6$ is:

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