Differentiate the function with respect to $x$: $2 \sqrt{\cot \left(x^{2}\right)}$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
Let $y = 2 \sqrt{\cot \left(x^{2}\right)}$.
Applying the chain rule,we differentiate with respect to $x$:
$\frac{dy}{dx} = 2 \cdot \frac{1}{2\sqrt{\cot(x^2)}} \cdot \frac{d}{dx}[\cot(x^2)]$
$= \frac{1}{\sqrt{\cot(x^2)}} \cdot [-\csc^2(x^2) \cdot \frac{d}{dx}(x^2)]$
$= \frac{1}{\sqrt{\frac{\cos(x^2)}{\sin(x^2)}}} \cdot [-\frac{1}{\sin^2(x^2)} \cdot 2x]$
$= -\sqrt{\frac{\sin(x^2)}{\cos(x^2)}} \cdot \frac{2x}{\sin^2(x^2)}$
$= -\frac{2x}{\sqrt{\cos(x^2) \sin(x^2) \sin(x^2)}}$
$= -\frac{2x}{\sin(x^2) \sqrt{\sin(x^2)\cos(x^2)}}$
Multiplying numerator and denominator by $\sqrt{2}$:
$= -\frac{2\sqrt{2}x}{\sin(x^2) \sqrt{2\sin(x^2)\cos(x^2)}}$
$= -\frac{2\sqrt{2}x}{\sin(x^2) \sqrt{\sin(2x^2)}}$

Explore More

Similar Questions

Let $F(x)=e^{x}$, $G(x)=e^{-x}$ and $H(x)=G(F(x))$, where $x$ is a real variable. Then, $\frac{dH}{dx}$ at $x=0$ is

$\frac{d}{dx} \left( \sqrt{x} + \frac{1}{\sqrt{x}} \right)^2 = $

Find the derivative of $\frac{2}{x+1}-\frac{x^{2}}{3x-1}$.

If $y=\sqrt{\frac{1+\tan x}{1-\tan x}}$,then $\frac{d y}{d x}=$

Find the derivative of the following function (it is to be understood that $a, b, c,$ and $d$ are fixed non-zero constants): $\frac{a x+b}{c x+d}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo