The dimensional formula of the universal gas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The ideal gas equation is given by $PV = nRT$,where $R$ is the universal gas constant.Rearranging for $R$,we get $R = \frac{PV}{nT}$.The dimension

Vedclass · Accepted Answer

$[M L^2 T^{-2} 	heta^{-1}]$

Vedclass · Answer

(A) The ideal gas equation is given by $PV = nRT$,where $R$ is the universal gas constant.Rearranging for $R$,we get $R = \frac{PV}{nT}$.The dimensions of pressure $P$ are $[M L^{-1} T^{-2}]$.The dimensions of volume $V$ are $[L^3]$.The dimensions of amount of substance $n$ are $[mol]$ (or often represented as dimensionless in basic dimensional analysis if $	heta$ represents temperature).The dimensions of temperature $T$ are $[	heta]$.Substituting these into the formula: $R = \frac{[M L^{-1} T^{-2}] 	imes [L^3]}{[	heta]} = [M L^2 T^{-2} 	heta^{-1}]$.Thus,the correct option is $A$.

The dimensional formula of the universal gas constant is:

Similar Questions

Which of the following physical quantities has no dimensions?

The dimensions of stress are

The dimension of $\frac{1}{{\sqrt {{\varepsilon _0}{\mu _0}} }}$ is that of

What is the dimensional formula for the ratio of angular momentum to linear momentum?

Select the pair whose dimensions are the same.

Vedclass Test Series

Exam Paper Generator

Online Exam Module