Dimethyl ether and ethyl alcohol are

The starting material is propene $(CH_3-CH=CH_2)$. The reaction with $H_3O^+$ (acid-catalyzed hydration) follows Markovnikov's rule to give $A$ (propan$-2-$ol,$CH_3-CH(OH)-CH_3$). The reaction with $(i) BH_3/THF$ followed by $(ii) H_2O_2/OH^-$ (hydroboration-oxidation) follows anti-Markovnikov's rule to give $B$ (propan$-1-$ol,$CH_3-CH_2-CH_2OH$). What is the relationship between products $A$ and $B$?

Select the correct pair.

Which of the following exhibits metamerism?

$C_6H_5C \equiv N$ and $C_6H_5N \equiv C$ exhibit which type of isomerism?

Which of the following will have one of the stereoisomers as a meso compound?