Dissolving $120 \ g$ of a compound (mol. wt $= 60$) in $1000 \ g$ of water gave a solution of density $1.12 \ g \ mL^{-1}$. The molarity of the solution is: (in $M$)

  • A
    $1.0$
  • B
    $2.0$
  • C
    $2.5$
  • D
    $4.0$

Explore More

Similar Questions

$A$ solution is prepared by adding $1 \ mole$ of ethyl alcohol in $9 \ mole$ of water. The mass percent of solute in the solution is. . . . . . . (Integer Answer)
(Given : Molar mass in $g \ mol^{-1}$ Ethyl alcohol : $46$,
water : $18$)

If the mole fraction of $H_2SO_4$ in an aqueous solution of $H_2SO_4$ is $0.1$,then the molality of the solution is ........... $m$.

Calculate the molarity of a solution containing $5 \, g$ of $NaOH$ in $450 \, mL$ solution. (in $, M$)

The sum of the mole fraction of the components of a solution is

Find out the mole fraction of glycerine in a solution containing $46 \ g$ of glycerine $(C_3H_8O_3)$ and $36 \ g$ of water $(H_2O)$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo