Dissolving NaCN in de-ionised water will resu | vedclass

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(D) When $NaCN$ is dissolved in de-ionised water, it undergoes hydrolysis as follows:$CN^{-} + H_2O \rightleftharpoons HCN + OH^{-}$Since $NaCN$ is a

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$pH > 7$

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(D) When $NaCN$ is dissolved in de-ionised water, it undergoes hydrolysis as follows:$CN^{-} + H_2O \rightleftharpoons HCN + OH^{-}$Since $NaCN$ is a salt of a strong base $(NaOH)$ and a weak acid $(HCN)$, the $CN^{-}$ ion undergoes anionic hydrolysis.This reaction produces $OH^{-}$ ions in the solution, making it basic.Therefore, the resulting solution will have a $pH > 7$.

Dissolving $NaCN$ in de-ionised water will result in a solution having

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