Divide $8 \sqrt{15}$ by $2 \sqrt{3}$.

  • A
    $5 \sqrt{5}$
  • B
    $4 \sqrt{4}$
  • C
    $4 \sqrt{5}$
  • D
    $5 \sqrt{4}$

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Simplify: $\frac{7 \sqrt{3}}{\sqrt{10}+\sqrt{3}}-\frac{2 \sqrt{5}}{\sqrt{6}+\sqrt{5}}-\frac{3 \sqrt{2}}{\sqrt{15}+3 \sqrt{2}}$

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Rationalise the denominator of $\frac{1}{\sqrt{2}}$.

Find the value of the following expression correct to three decimal places,rationalizing the denominator if needed. Given $\sqrt{2} = 1.414$,$\sqrt{3} = 1.732$,and $\sqrt{5} = 2.236$.
$\frac{1}{\sqrt{3} + \sqrt{2}}$

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Fill in the blanks to make the following statement true:
$\sqrt{1 \frac{25}{144}} = \ldots$

If $\sqrt{2} = 1.4142$,then evaluate $\sqrt{5} \div \sqrt{10}$ correct to four decimal places.

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