Do the following equations represent a pair of coincident lines? Justify your answer.
$3x + \frac{1}{7}y = 3$
$7x + 3y = 7$

(B) The condition for two lines to be coincident is $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$.
Given the pair of linear equations:
$3x + \frac{1}{7}y - 3 = 0$
$7x + 3y - 7 = 0$
Here,the coefficients are:
$a_1 = 3, b_1 = \frac{1}{7}, c_1 = -3$
$a_2 = 7, b_2 = 3, c_2 = -7$
Calculating the ratios:
$\frac{a_1}{a_2} = \frac{3}{7}$
$\frac{b_1}{b_2} = \frac{1/7}{3} = \frac{1}{21}$
$\frac{c_1}{c_2} = \frac{-3}{-7} = \frac{3}{7}$
Since $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$,the lines are not coincident. They intersect at a unique point.