Do the following pair of linear equations have no solution? Justify your answer.
$2x + 4y = 3$
$x = 2y$

(B) The condition for a pair of linear equations to have no solution is $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$.
Given equations are:
$2x + 4y - 3 = 0$
$x - 2y = 0$
Here,$a_1 = 2, b_1 = 4, c_1 = -3$ and $a_2 = 1, b_2 = -2, c_2 = 0$.
Calculating the ratios:
$\frac{a_1}{a_2} = \frac{2}{1} = 2$
$\frac{b_1}{b_2} = \frac{4}{-2} = -2$
Since $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$ $(2 \neq -2)$,the lines intersect at a unique point.
Therefore,the given pair of linear equations has a unique solution,not 'no solution'.