Draw graphs of beats produced by two harmonic waves of frequency $11 \ Hz$ and $9 \ Hz$.
(N/A) The time-displacement graphs of two waves of frequency $11 \ Hz$ and $9 \ Hz$ are shown in figure $(a)$ and $(b)$.
The result of their superposition is shown in figure $(c)$.
Beats are the periodic variation in intensity at a given point due to the superposition of two sound waves of slightly different frequencies. The beat frequency is given by $f_{beat} = |f_1 - f_2| = |11 \ Hz - 9 \ Hz| = 2 \ Hz$. This means there are $2$ beats per second.
The result of their superposition is shown in figure $(c)$.
Beats are the periodic variation in intensity at a given point due to the superposition of two sound waves of slightly different frequencies. The beat frequency is given by $f_{beat} = |f_1 - f_2| = |11 \ Hz - 9 \ Hz| = 2 \ Hz$. This means there are $2$ beats per second.
Explore More
Similar Questions
On sounding tuning fork $A$ with another tuning fork $B$ of frequency $384 \ Hz$,$6$ beats are produced per second. After loading the prongs of $A$ with some wax and then sounding it again with $B$,$4$ beats are produced per second. What is the frequency of the tuning fork $A$ in $Hz$?
Medium
View Solution$A$ tuning fork $A$ of frequency $200 \ Hz$ is sounded with fork $B,$ the number of beats per second is $5.$ By putting some wax on $A,$ the number of beats increases to $8.$ The frequency of fork $B$ is .... $Hz$
Medium
View SolutionWhen two tuning forks (fork $1$ and fork $2$) are sounded together,$4$ beats per second are heard. Now some tape is attached to the prong of fork $2$. When the tuning forks are sounded again,$6$ beats per second are heard. If the frequency of fork $1$ is $200 \,Hz$,then the original frequency of fork $2$ is ........... $Hz$.
Difficult
View SolutionIf three sources of sound of frequencies $(n-1)$, $n$, and $(n+1)$ are vibrated together, the number of beats produced and heard per second respectively are
Two tuning forks $A$ and $B$ produce $8 \, Hz$ beats per second when sounded together. $A$ gas column $37.5 \, cm$ long in a pipe closed at one end resonates in its fundamental mode with fork $A$,whereas a column of length $38.5 \, cm$ of the same gas in a similar pipe is required for resonance with fork $B$. The frequencies of these two tuning forks are:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo