Draw the graph of the linear equation in two variables: $3 = 2x + y$
(N/A) $y = 3 - 2x$
$\therefore$ If $x = 0$,then $y = 3 - 2(0) \Rightarrow y = 3$
If $x = 1$,then $y = 3 - 2(1) \Rightarrow y = 1$
If $x = 2$,then $y = 3 - 2(2) \Rightarrow y = -1$
$\therefore$ We get the following table:
Plot the ordered pairs $(0, 3)$,$(1, 1)$,and $(2, -1)$ on the graph paper. Joining these points,we get a line $CD$.
Thus,the line $CD$ is the required graph of $3 = 2x + y$.
$\therefore$ If $x = 0$,then $y = 3 - 2(0) \Rightarrow y = 3$
If $x = 1$,then $y = 3 - 2(1) \Rightarrow y = 1$
If $x = 2$,then $y = 3 - 2(2) \Rightarrow y = -1$
$\therefore$ We get the following table:
| $x$ | $0$ | $1$ | $2$ |
| $y$ | $3$ | $1$ | $-1$ |
Plot the ordered pairs $(0, 3)$,$(1, 1)$,and $(2, -1)$ on the graph paper. Joining these points,we get a line $CD$.
Thus,the line $CD$ is the required graph of $3 = 2x + y$.
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