Draw the graph of the following linear equation in two variables:
$2x - 3y = 0$

(N/A) Given equation: $2x - 3y = 0$
$\therefore 3y = 2x$
$\therefore y = \frac{2}{3}x$
To draw the graph,we find at least two solutions for the equation:
$1$. For $x = 0$,we get $y = \frac{2}{3}(0) = 0$. So,the point is $(0, 0)$.
$2$. For $x = 3$,we get $y = \frac{2}{3}(3) = 2$. So,the point is $(3, 2)$.
$3$. For $x = -3$,we get $y = \frac{2}{3}(-3) = -2$. So,the point is $(-3, -2)$.
We can represent these solutions in the tabular form as below:

$x$	$0$	$3$	$-3$
$y$	$0$	$2$	$-2$

Plot these points on a Cartesian plane and join them to obtain the straight line representing the equation $2x - 3y = 0$.