Draw the structure of the compound having molecular formula $C_7H_8$ and determine the number of $\sigma$ and $\pi$ bonds.

(N/A) The compound with molecular formula $C_7H_8$ is toluene $(C_6H_5CH_3)$.
Structure analysis:
$1$. The benzene ring contains $3$ $\pi$-bonds.
$2$. The benzene ring has $6$ $C-C$ $\sigma$-bonds and $6$ $C-H$ $\sigma$-bonds.
$3$. The methyl group $(CH_3)$ attached to the ring has $1$ $C-C$ $\sigma$-bond and $3$ $C-H$ $\sigma$-bonds.
Total $\sigma$-bonds = $6$ (ring $C-C$) + $6$ (ring $C-H$) + $1$ (exocyclic $C-C$) + $3$ (methyl $C-H$) = $15$ $\sigma$-bonds.
Total $\pi$-bonds = $3$ $\pi$-bonds.