The dual of $(x \vee y) \wedge (x \vee 1) = x \vee (x \wedge y) \vee y$ is
- A$(x \wedge y) \vee (x \wedge 0) = x \wedge (x \vee y) \wedge y$
- B$(x \vee y) \vee (x \wedge 1) = x \wedge (x \vee y) \wedge y$
- C$(x \wedge y) \wedge (x \wedge 0) = x \wedge (x \vee y) \wedge y$
- DNone of these
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Similar Questions
If $p$ and $q$ are true statements and $r$ is a false statement,then which of the following statements is true?
Consider the following statements.
$p$: If $3^4 > 4^3$, then $3^3 > 4^4$
$q$: The roots of the equation $x^2 - 2x + 2 = 0$ are real if and only if Mumbai is in Maharashtra.
$r$: Statement $p$ is true or statement $q$ is false.
Which of the following has truth value $T$ (true)?
$p$: If $3^4 > 4^3$, then $3^3 > 4^4$
$q$: The roots of the equation $x^2 - 2x + 2 = 0$ are real if and only if Mumbai is in Maharashtra.
$r$: Statement $p$ is true or statement $q$ is false.
Which of the following has truth value $T$ (true)?
DifficultMHT CET 2026
View SolutionLet $S$ be a non-empty subset of $\mathbb{R}$. Consider the following statement:
$p$ : There is a rational number $x \in S$ such that $x > 0$.
Which of the following statements is the negation of the statement $p$?
$p$ : There is a rational number $x \in S$ such that $x > 0$.
Which of the following statements is the negation of the statement $p$?
The negation of the statement pattern $(p \wedge \sim q) \rightarrow (p \vee \sim q)$ is
Consider the following statements:
$r$: If $p \to q$ is false then $p \lor q$ is false.
$s$: If $p \leftrightarrow q$ is false then $p \lor q$ is false.
The truth values of $r \to s$ and $s \to r$ are respectively . . . . . .
$r$: If $p \to q$ is false then $p \lor q$ is false.
$s$: If $p \leftrightarrow q$ is false then $p \lor q$ is false.
The truth values of $r \to s$ and $s \to r$ are respectively . . . . . .
DifficultMHT CET 2026
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