(C) In negative $\beta$-decay,a neutron $(n)$ inside the nucleus transforms into a proton $(p)$,an electron $(_{-1}e^0)$,and an antineutrino $(\bar{\n

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$A$ neutron in the nucleus decays emitting an electron

(C) In negative $\beta$-decay,a neutron $(n)$ inside the nucleus transforms into a proton $(p)$,an electron $(_{-1}e^0)$,and an antineutrino $(\bar{\nu})$.The process is represented as: $n \to p + _{-1}e^0 + \bar{\nu}$.Therefore,the correct statement is that a neutron in the nucleus decays,emitting an electron.