During a thermodynamic process, the increase | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the first law of thermodynamics, the change in internal energy $(\Delta U)$ is given by $\Delta U = Q + W$, where $Q$ is the heat add

Vedclass · Accepted Answer

Adiabatic

Vedclass · Answer

(B) According to the first law of thermodynamics, the change in internal energy $(\Delta U)$ is given by $\Delta U = Q + W$, where $Q$ is the heat added to the system and $W$ is the work done on the system.Given that the increase in internal energy is equal to the work done on the system, we have $\Delta U = W$.Comparing this with the first law equation, we get $Q = 0$.A thermodynamic process in which no heat is exchanged with the surroundings $(Q = 0)$ is known as an adiabatic process.Therefore, the correct option is $B$.

During a thermodynamic process, the increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo?

Similar Questions

In an adiabatic expansion,the product of pressure and volume:

$A$ monoatomic gas at pressure $P$ and volume $V$ is suddenly compressed to one-eighth of its original volume. The final pressure at constant entropy will be $.....P$.

When a gas expands adiabatically, its volume is doubled while its absolute temperature is decreased by a factor of $2$. The value of the adiabatic constant $\gamma$ is

The $P-V$ diagram for two gases during an adiabatic process is shown in the figure. Curves $A$ and $B$ correspond to:

$P-V$ plots for two gases during an adiabatic process are shown in the figure. Plots $(1)$ and $(2)$ correspond respectively to

Vedclass Test Series

Exam Paper Generator

Online Exam Module