During the debromination of meso-2,3-dibromob | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The debromination of $meso-2,3-dibromobutane$ proceeds via an $E2$ mechanism,which is stereospecific. In the $meso$ form,the two bromine atoms are

Vedclass · Accepted Answer

$trans-2-butene$

Vedclass · Answer

(D) The debromination of $meso-2,3-dibromobutane$ proceeds via an $E2$ mechanism,which is stereospecific. In the $meso$ form,the two bromine atoms are anti to each other in the staggered conformation. Elimination of $Br_2$ from this conformation leads to the formation of $trans-2-butene$. $trans-2-butene$ is more stable than $cis-2-butene$ due to reduced steric hindrance between the methyl groups.

During the debromination of $meso-2,3-dibromobutane$,the major compound formed is:

Similar Questions

Isobutene in the presence of dilute $H_2SO_4$ forms an alcohol. The major product is

Alkene can be prepared from alkyl halide by the following reagent: $R-CH_2-CH_2-X + \text{Base} \to \text{Alkene} + \text{Base-H} + X^-$

Identify the species $X$ in the reaction: $CH_3-CH=CH_2 + [O] \xrightarrow{\text{conc. acidic } KMnO_4} X + HCOOH$

Addition of $HI$ on the double bond of propene yields isopropyl iodide and not $n$-propyl iodide as the major product. This is because the addition proceeds through

Provide the structural formula for $2$-methyl-$2$-butene.

Vedclass Test Series

Exam Paper Generator

Online Exam Module