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(C) In a lead accumulator (lead-acid battery),the cathode is made of lead dioxide $(PbO_{2_{(s)}})$.
During the discharging process,the reaction at t

Vedclass · Accepted Answer

$PbO_{2_{(s)}}$ is reduced to $Pb^{2+}_{(aq.)}$

Vedclass · Answer

(C) In a lead accumulator (lead-acid battery),the cathode is made of lead dioxide $(PbO_{2_{(s)}})$.
During the discharging process,the reaction at the cathode is: $PbO_{2	ext{(s)}} + 4H^{+}{_{	ext{(aq)}}} + SO_4^{2-}{_{	ext{(aq)}}} + 2e^{-} ightarrow PbSO_{4	ext{(s)}} + 2H_2O_{	ext{(l)}}$.
In this reaction,the oxidation state of $Pb$ in $PbO_{2}$ changes from $+4$ to $+2$ in $PbSO_{4}$.
Since the oxidation state decreases,$PbO_{2_{(s)}}$ is reduced to $Pb^{2+}$ ions (which then form $PbSO_{4_{(s)}}$).

List-$I$ (Applications)	List-$II$ (Batteries/Cell)
$A$. Transistors	$I$. Anode $- Zn/Hg$; Cathode $- HgO + C$
$B$. Hearing aids	$II$. Hydrogen fuel cell
$C$. Inverters	$III$. Anode $- Zn$; Cathode $- Carbon$
$D$. Apollo space ship	$IV$. Anode $- Pb$; Cathode $- PbO_2$

During discharging,the change taking place at the cathode in a lead accumulator is:

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