During the estimation of oxalic acid $V/S$ $KMnO_4$,the self-indicator is:

  • A
    $KMnO_4$
  • B
    Oxalic acid
  • C
    $K_2SO_4$
  • D
    $MnSO_4$

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Similar Questions

Can titrations with $KMnO_4$ be performed in the presence of $HCl$? Why?

In a conductometric titration,a small volume of titrant of higher concentration is added stepwise to a larger volume of titrate of much lower concentration,and the conductance is measured after each addition.
The limiting ionic conductivity ( $\Lambda ^0$ ) values (in $mS \ m ^2 \ mol ^{-1}$ ) for different ions in aqueous solutions are given below:
Ions$Ag ^{+}$$K ^{+}$$Na ^{+}$$H ^{+}$$NO _3^{-}$$Cl ^{-}$$SO _4^{2-}$$OH ^{-}$$CH _3COO ^{-}$
$\Lambda _0$$6.2$$7.4$$5.0$$35.0$$7.2$$7.6$$16.0$$19.9$$4.1$

For different combinations of titrates and titrants given in List-$I$,the graphs of 'conductance' versus 'volume of titrant' are given in List-$II$.
List-$I$List-$II$
$(P)$ Titrate: $KCl$,Titrant: $AgNO _3$$(1)$ Graph showing initial decrease then increase
$(Q)$ Titrate: $AgNO _3$,Titrant: $KCl$$(2)$ Graph showing sharp decrease then sharp increase
$(R)$ Titrate: $NaOH$,Titrant: $HCl$$(3)$ Graph showing slight decrease then increase
$(S)$ Titrate: $NaOH$,Titrant: $CH _3COOH$$(4)$ Graph showing continuous increase
$(5)$ Graph showing decrease then constant

Match each entry in List-$I$ with the appropriate entry in List-$II$ and choose the correct option.

An aqueous solution of $6.3 \ g$ of oxalic acid dihydrate is made up to $250 \ mL$. The volume of $0.1 \ N \ NaOH$ required to completely neutralise $10 \ mL$ of this solution is.......$mL$

Eosin used to detect the end point of precipitation titration by adsorption is called:

In the titration of $I_{2(aq)}$ by $S_2O_3^{2-}{_{\text{(aq)}}}$ using the starch indicator, the end point is indicated by:

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