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(D) The correct answer is $D$.$1$. At the resting state,the inner side of the axonal membrane is negatively charged relative to the outer side due to

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First negative,then positive and again back to negative.

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(D) The correct answer is $D$.$1$. At the resting state,the inner side of the axonal membrane is negatively charged relative to the outer side due to the differential permeability of the membrane to $K^+$ and $Na^+$ ions.$2$. When a stimulus is applied,the membrane becomes permeable to $Na^+$ ions,causing an influx of $Na^+$. This leads to depolarization,where the inner side becomes positively charged.$3$. Subsequently,the membrane becomes permeable to $K^+$ ions,which move out,leading to repolarization,where the inner side returns to its original negative state.$4$. Thus,the potential changes from negative to positive and back to negative during the transmission of an action potential.

During the transmission of a nerve impulse through a nerve fibre,the potential on the inner side of the plasma membrane has which type of electric change?

Similar Questions

What is the speed of nerve impulse conduction in mammalian nerve fibers?

In a neuron,the absence of which of the following is observed in response to different types of stimuli?

$A$: Presence of myelin sheath increases the rate of conduction of nerve impulse.
$R$: Ionic channels are absent in the area covered by myelin sheath; therefore,depolarization occurs only at the nodes of Ranvier,resulting in saltatory or jumping conduction.

Depolarization of a stimulated nerve is maintained by

What is the conduction of an action potential at the Nodes of Ranvier called?

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