(A) The energy released per fission is $E = 200 \text{ MeV}$.Converting this to Joules: $E = 200 \times 10^6 \times 1.6 \times 10^{-19} \text{ J} = 3.

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(A) The energy released per fission is $E = 200 \text{ MeV}$.Converting this to Joules: $E = 200 \times 10^6 \times 1.6 \times 10^{-19} \text{ J} = 3.2 \times 10^{-11} \text{ J}$.The power generated by the reactor is $P = 1 \text{ MW} = 10^6 \text{ W} = 10^6 \text{ J/s}$.The rate of fission $R$ is given by the formula $R = P / E$.$R = 10^6 / (3.2 \times 10^{-11}) = (1 / 3.2) \times 10^{17} = 0.3125 \times 10^{17} = 3.125 \times 10^{16} \text{ fissions/s}$.

Class 12 Physics Nuclei Nuclear Fission, Fusion and Nuclear Reactor

Medium

Each nuclear fission of ${}^{235}U$ releases $200 \text{ MeV}$ of energy. If a reactor generates $1 \text{ MW}$ power,then the rate of fission in the reactor is:

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A
$3.125 \times 10^{16}$
B
$3.125 \times 10^{10}$
C
$3.125 \times 10^8$
D
$3.125 \times 10^6$

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Nuclei

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Nuclear Fission, Fusion and Nuclear Reactor

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Each nuclear fission of ${}^{235}U$ releases $200 \text{ MeV}$ of energy. If a reactor generates $1 \text{ MW}$ power,then the rate of fission in the reactor is:

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