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(D) The original alphabet series is divided into two halves: $A-M$ (first half) and $N-Z$ (second half).If the second half is reversed,the series beco

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$U$

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(D) The original alphabet series is divided into two halves: $A-M$ (first half) and $N-Z$ (second half).If the second half is reversed,the series becomes:$A, B, C, D, E, F, G, H, I, J, K, L, M$$Z, Y, X, W, V, U, T, S, R, Q, P, O, N$The twelfth letter from the right in this new series is $Y$ (counting from $N$ as $1$,$O$ as $2$,...,$Y$ as $12$).Now,we need to find the fourth letter to the left of $Y$.Counting to the left from $Y$: $X(1), W(2), V(3), U(4)$.Therefore,the fourth letter to the left of $Y$ is $U$.

Each of the following questions is based on the following alphabet series.
$A, B, C, D, E, F, G, H, I, J, K, L, M$
$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$
Which letter should be fourth to the left of the twelfth letter from the right if the second half of the given alphabet is reversed?

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Each of the following questions is based on the following alphabet series.$A, B, C, D, E, F, G, H, I, J, K, L, M$$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$Which letter should be fourth to the left of the twelfth letter from the right if the second half of the given alphabet is reversed?