The effective resistance across AB in the net | vedclass

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(B) $1$. The two resistors of $2 \,\Omega$ each are connected in parallel. Their equivalent resistance $R_1$ is given by: $\frac{1}{R_1} = \frac{1}{2}

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$3$

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(B) $1$. The two resistors of $2 \,\Omega$ each are connected in parallel. Their equivalent resistance $R_1$ is given by: $\frac{1}{R_1} = \frac{1}{2} + \frac{1}{2} = 1 \implies R_1 = 1 \,\Omega$.$2$. The two resistors of $4 \,\Omega$ each are connected in parallel. Their equivalent resistance $R_2$ is given by: $\frac{1}{R_2} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4} = \frac{1}{2} \implies R_2 = 2 \,\Omega$.$3$. Now,$R_1$ and $R_2$ are in series. The total effective resistance $R_{net} = R_1 + R_2 = 1 \,\Omega + 2 \,\Omega = 3 \,\Omega$.

The effective resistance across $AB$ in the network shown is .......... $\Omega$.

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