Eight chairs are numbered 1 to 8. Two women a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $1$: The two women choose their chairs from the chairs marked $1$ to $4$. Since the order in which they sit matters (as chairs are distinct),

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) Step $1$: The two women choose their chairs from the chairs marked $1$ to $4$. Since the order in which they sit matters (as chairs are distinct),the number of ways is $^4P_2 = 4 	imes 3 = 12$.Step $2$: After the women have occupied $2$ chairs,there are $8 - 2 = 6$ chairs remaining in total.Step $3$: The three men then choose their chairs from the remaining $6$ chairs. The number of ways is $^6P_3 = 6 	imes 5 	imes 4 = 120$.Step $4$: The total number of arrangements is the product of these two steps: $^4P_2 	imes ^6P_3 = 12 	imes 120 = 1440$.Since $1440$ is not listed in options $A, B,$ or $C$,the correct answer is $D$.

Eight chairs are numbered $1$ to $8$. Two women and three men wish to occupy one chair each. First,the women choose the chairs from amongst the chairs marked $1$ to $4$,and then men select the chairs from amongst the remaining. The number of possible arrangements is

Similar Questions

Out of $13$ cricket players,$4$ are bowlers. In how many ways can a cricket team of $11$ players be formed such that at least $2$ bowlers are included?

Given $6$ different letters of an alphabet. Words with $4$ letters are formed from these given letters. The number of words which have at least one letter repeated and no two same letters are together,is:

$\sum_{0 \le i < j \le n} i \binom{n}{j}$ is equal to

$A$ five-digit number divisible by $3$ has to be formed using the numerals $0, 1, 2, 3, 4,$ and $5$ without repetition. The total number of ways in which this can be done is

$^nC_r + ^{n-1}C_r + ...... + ^rC_r$ =

Vedclass Test Series

Exam Paper Generator

Online Exam Module