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(A) Let the total rent of the car be $x$.When $8$ persons share the rent,the share of each person is $\frac{x}{8}$.When one person withdraws,the numbe

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$\frac{1}{7}$

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(A) Let the total rent of the car be $x$.When $8$ persons share the rent,the share of each person is $\frac{x}{8}$.When one person withdraws,the number of persons remaining is $8 - 1 = 7$.Now,the share of each of the $7$ persons is $\frac{x}{7}$.The increase in the share of each person is $\frac{x}{7} - \frac{x}{8} = \frac{8x - 7x}{56} = \frac{x}{56}$.To find the fraction by which the share increases,we divide the increase by the original share:$	ext{Increase fraction} = \frac{\frac{x}{56}}{\frac{x}{8}} = \frac{x}{56} 	imes \frac{8}{x} = \frac{8}{56} = \frac{1}{7}$.

Eight persons are planning to share equally the rent of a car. If one person withdraws from the arrangement and the others share equally the entire cost of the car,then the share of each of the remaining persons increases by what fraction?

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