Elements X and Y belong to Group 15. The diff | vedclass

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(A) The electronegativity $(EN)$ values for Group $15$ elements are as follows:Element$EN$$N$$3.0$$P$$2.1$$As$$2.0$$Sb$$1.9$$Bi$$1.9$Given that the di

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$N$ and $As$

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(A) The electronegativity $(EN)$ values for Group $15$ elements are as follows:Element$EN$$N$$3.0$$P$$2.1$$As$$2.0$$Sb$$1.9$$Bi$$1.9$Given that the difference between $EN(X)$ and $EN(P)$ is greater than the difference between $EN(P)$ and $EN(Y)$.Let $X = N$ $(EN = 3.0)$ and $Y = As$ $(EN = 2.0)$.$|EN(N) - EN(P)| = |3.0 - 2.1| = 0.9$$|EN(P) - EN(As)| = |2.1 - 2.0| = 0.1$Since $0.9 > 0.1$, the condition is satisfied. Thus, $X$ is $N$ and $Y$ is $As$.

Elements $X$ and $Y$ belong to Group $15$. The difference between the electronegativity values of $X$ and phosphorus is higher than that of the difference between phosphorus and $Y$. $X$ and $Y$ are respectively:

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