The end product of the above reaction is:

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(A) $1$. Esterification: Naphthalene$-1-$acetic acid reacts with $EtOH/H^+$ to form ethyl naphthalene$-1-$acetate.$2$. Alkylation: Treatment with $NaH

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(A) $1$. Esterification: Naphthalene$-1-$acetic acid reacts with $EtOH/H^+$ to form ethyl naphthalene$-1-$acetate.$2$. Alkylation: Treatment with $NaH$ followed by $MeI$ results in the formation of ethyl $2-$(naphthalen$-1-$yl)propanoate.$3$. Hydrolysis: Basic hydrolysis followed by acidification gives $2-$(naphthalen$-1-$yl)propanoic acid.$4$. Cyclization: Treatment with $SOCl_2$ converts the carboxylic acid to an acid chloride,which then undergoes intramolecular Friedel-Crafts acylation in the presence of $AlCl_3$ to form the cyclic ketone,$2$-methyl$-2,3-$dihydro-1H-cyclopenta[a]naphthalen$-1-$one.

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