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(D) The reaction sequence is as follows:$1$. $CH_3CH_2NH_2 \xrightarrow{KMnO_4/H^+} CH_3COOH$ (Oxidation of primary amine to carboxylic acid).$2$. $CH

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$CH_3NH_2$

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(D) The reaction sequence is as follows:$1$. $CH_3CH_2NH_2 \xrightarrow{KMnO_4/H^+} CH_3COOH$ (Oxidation of primary amine to carboxylic acid).$2$. $CH_3COOH \xrightarrow{SOCl_2} CH_3COCl$ (Conversion of carboxylic acid to acid chloride).$3$. $CH_3COCl \xrightarrow{NH_3, \Delta} CH_3CONH_2$ (Ammonolysis of acid chloride to amide).$4$. $CH_3CONH_2 \xrightarrow{NaOH/Br_2} CH_3NH_2$ (Hofmann bromamide degradation reaction).Thus,the end product is $CH_3NH_2$.

What is the end product of the following reaction sequence?
$CH_3CH_2NH_2$ $\xrightarrow[H^+]{KMnO_4}$ $\xrightarrow{SOCl_2}$ $\xrightarrow[\Delta]{NH_3}$ $\xrightarrow{NaOH/Br_2} ?$

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What is the end product of the following reaction sequence?$CH_3CH_2NH_2$ $\xrightarrow[H^+]{KMnO_4}$ $\xrightarrow{SOCl_2}$ $\xrightarrow[\Delta]{NH_3}$ $\xrightarrow{NaOH/Br_2} ?$