Energy generation in stars is mainly due to

  • A
    Chemical reactions
  • B
    Fission of heavy nuclei
  • C
    Fusion of light nuclei
  • D
    Fusion of heavy nuclei

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Similar Questions

The mass of a nucleus ${ }_Z^A X$ is less than the sum of the masses of $(A-Z)$ neutrons and $Z$ protons. The energy equivalent to this mass difference is the binding energy. $A$ heavy nucleus of mass $M$ can break into two light nuclei of masses $m_1$ and $m_2$ only if $M > (m_1+m_2)$. The masses of some neutral atoms are given in the table below:
${ }_1^1 H$: $1.007825 u$${ }_1^2 H$: $2.014102 u$${ }_1^3 H$: $3.016050 u$${ }_2^4 He$: $4.002603 u$
${ }_3^6 Li$: $6.015123 u$${ }_3^7 Li$: $7.016004 u$${ }_{30}^{70} Zn$: $69.925325 u$${ }_{34}^{82} Se$: $81.916709 u$
${ }_{64}^{152} Gd$: $151.919803 u$${ }_{82}^{206} Pb$: $205.974455 u$${ }_{83}^{209} Bi$: $208.980388 u$${ }_{84}^{210} Po$: $209.982876 u$

$1.$ The correct statement is:
$(A)$ The nucleus ${ }_3^6 Li$ can emit an alpha particle.
$(B)$ The nucleus ${ }_{84}^{210} Po$ can emit a proton.
$(C)$ Deuteron $({ }_1^2 H)$ and alpha particle $({ }_2^4 He)$ can undergo complete fusion.
$(D)$ The nuclei ${ }_{30}^{70} Zn$ and ${ }_{34}^{82} Se$ can undergo complete fusion.
$2.$ The kinetic energy (in $keV$) of the alpha particle, when the nucleus ${ }_{84}^{210} Po$ at rest undergoes alpha decay, is:
$(A)$ $5319$ $(B)$ $5422$ $(C)$ $5707$ $(D)$ $5818$

In a nuclear reactor,the function of the moderator is to decrease

Nuclear fission is possible because the binding energy per nucleon ..........

The scientific principle that forms the basis of the Tokamak technology is

In an atomic reactor and an atomic bomb,the multiplication factor $(r)$ per fission is respectively:

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