Energy levels A, B, C of a certain atom corre | vedclass

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Question

(B) The energy difference for the transition from $C$ to $A$ is the sum of the energy differences for the transitions from $C$ to $B$ and $B$ to $A$.$

Vedclass · Accepted Answer

$\lambda_3 = \frac{\lambda_1 \lambda_2}{\lambda_1 + \lambda_2}$

Vedclass · Answer

(B) The energy difference for the transition from $C$ to $A$ is the sum of the energy differences for the transitions from $C$ to $B$ and $B$ to $A$.$E_C - E_A = (E_C - E_B) + (E_B - E_A)$Since energy $E = \frac{hc}{\lambda}$, we can write:$\frac{hc}{\lambda_3} = \frac{hc}{\lambda_1} + \frac{hc}{\lambda_2}$Dividing both sides by $hc$:$\frac{1}{\lambda_3} = \frac{1}{\lambda_1} + \frac{1}{\lambda_2}$$\frac{1}{\lambda_3} = \frac{\lambda_2 + \lambda_1}{\lambda_1 \lambda_2}$Therefore, $\lambda_3 = \frac{\lambda_1 \lambda_2}{\lambda_1 + \lambda_2}$.

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