Energy of a photon whose frequency is 10^{12} | vedclass

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Question

(D) The energy of a photon is given by the formula $E = h
u$.Given frequency $
u = 10^{12} 	ext{ MHz} = 10^{12} 	imes 10^6 	ext{ Hz} = 10^{18}

Vedclass · Accepted Answer

$4.14 	imes 10^3 	ext{ eV}$

Vedclass · Answer

(D) The energy of a photon is given by the formula $E = h
u$.Given frequency $
u = 10^{12} 	ext{ MHz} = 10^{12} 	imes 10^6 	ext{ Hz} = 10^{18} 	ext{ Hz}$.Planck's constant $h = 6.63 	imes 10^{-34} 	ext{ Js}$.To convert the energy from Joules to electron-volts (eV),we divide by the elementary charge $e = 1.6 	imes 10^{-19} 	ext{ C}$.$E(	ext{eV}) = \frac{h
u}{e} = \frac{6.63 	imes 10^{-34} 	imes 10^{18}}{1.6 	imes 10^{-19}}$.$E(	ext{eV}) = \frac{6.63}{1.6} 	imes 10^{-34 + 18 + 19} = 4.14375 	imes 10^3 	ext{ eV}$.Rounding to significant figures,$E \approx 4.14 	imes 10^3 	ext{ eV}$.

Energy of a photon whose frequency is $10^{12} \text{ MHz}$ is
[ Planck's constant,$h = 6.63 \times 10^{-34} \text{ Js}, e = 1.6 \times 10^{-19} \text{ C}$ ]

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Energy of a photon whose frequency is $10^{12} \text{ MHz}$ is[ Planck's constant,$h = 6.63 \times 10^{-34} \text{ Js}, e = 1.6 \times 10^{-19} \text{ C}$ ]