The energy of a quantum of frequency $10^{15} \ Hz$ and $h = 6.6 \times 10^{-34} \ J \cdot s$ will be:

  • A
    $6.6 \times 10^{-19} \ J$
  • B
    $6.6 \times 10^{-12} \ J$
  • C
    $6.6 \times 10^{-49} \ J$
  • D
    $6.6 \times 10^{-41} \ J$

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$A$ $100\,W$ light source is emitting radiation of wavelength $5000\,\mathring{A}$. The rate of emission of photons is of the order of:

If the energy of a photon is expressed in units of $KeV$ and the wavelength in units of $\mathring{A}$,then the energy of the photon can be calculated by:

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