Ethyl alcohol on oxidation with K_2Cr_2O_7 gi | vedclass

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Question

(A) Ethyl alcohol $(CH_3CH_2OH)$ is a primary alcohol. When it undergoes oxidation with a strong oxidizing agent like $K_2Cr_2O_7$ in an acidic medium

Vedclass · Accepted Answer

Acetic acid

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(A) Ethyl alcohol $(CH_3CH_2OH)$ is a primary alcohol. When it undergoes oxidation with a strong oxidizing agent like $K_2Cr_2O_7$ in an acidic medium,it is first oxidized to acetaldehyde $(CH_3CHO)$ and then further oxidized to acetic acid $(CH_3COOH)$. The overall reaction is: $CH_3CH_2OH \xrightarrow{[O]} CH_3COOH$.

Ethyl alcohol on oxidation with $K_2Cr_2O_7$ gives

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